Michael Conforto

So the big-name MLB free agents are mostly off the board by now, and the San Francisco Giants picked up … well, it’s not looking good so far.

They whiffed in spectacular fashion on Carlos Correa. And they missed out on Aaron Judge and Justin Verlander. Also, they failed in their pursuit of Trea Turner and Xander Bogaerts.

So Giants fans, who are mad the team has yet to make a marquee free agent signing this offseason, aren’t going to be satisfied with a report by the San Francisco Chronicle‘s Susan Slusser that the team is reportedly pursuing slugger Michael Conforto.

Yes, that Michael Conforto. The former New York Mets slugger has an All-Star appearance (2017), but he also missed the entire 2022 season after undergoing shoulder surgery.

Many Giants fans are furious about the turn of events involving Correa and Conforto (coincidentally both Scott Boras clients). Correa, of course, had reportedly agreed to a massive 13-year, $350 million deal with the Giants Tuesday, only to back out when the team expressed concern about an old injury from his minor league days. He signed with the Mets on Wednesday.

Now comes the report the team is interested in Conforto, who underwent shoulder surgery and missed all of 2022.

Giants fans see this as the final straw for a miserable offseason.

“The Giants pass on Correa from an injury in 2014 that hasn’t hampered him during his MLB tenure …but they’re interested in Michael Conforto, who has recently had a significant shoulder injury. Ok,” tweeted Doug Hayes.

“You can’t make this stuff up,” noted Carol Tieso.

“First step in acquiring Michael Conforto: let the Giants acquire Michael Conforto,” joked another fan.

“Didn’t he miss like oh I don’t know… AN ENTIRE YEAR WITH INJURY,” noted one angry fan.

“No worries, he will pass his physical with the Giants,” tweeted a fan.

 

[Doug Hayes]

About Arthur Weinstein

Arthur spends his free time traveling around the U.S. to sporting events, state and national parks, and in search of great restaurants off the beaten path.